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9m^2+2m=12
We move all terms to the left:
9m^2+2m-(12)=0
a = 9; b = 2; c = -12;
Δ = b2-4ac
Δ = 22-4·9·(-12)
Δ = 436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{436}=\sqrt{4*109}=\sqrt{4}*\sqrt{109}=2\sqrt{109}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{109}}{2*9}=\frac{-2-2\sqrt{109}}{18} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{109}}{2*9}=\frac{-2+2\sqrt{109}}{18} $
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